Question024 (part 1 of 3 ) 10.0 points A 4.0 kg block is pushed 2.0 m at a constant velocity up a vertical wall by a constant force applied at an angle of $26.0^{\circ}$ with the horizontal, as shown in the figure.
The acceleration of gravity is $9.81 \mathrm{~m} / \mathrm{s}^{2}$ .
Drawing not to scale. If the coefficient of kinetic friction between the block and the wall is 0.20 , find a) the work done by the force on the block. Answer in units of J.
025 (part 2 of 3 ) 10.0 points b) the work done by gravity on the block. Answer in units of J .
026 (part 3 of 3 ) 10.0 points c) the magnitude of the normal force between the block and the wall.
Answer in units of N .

Studdy Solution
Calculate the magnitude of the normal force between the block and the wall.
3.1 Use the horizontal component of the force:
$N = F_{\text{horizontal}} = F \cos(26^\circ)$
Substitute the calculated $F$ from STEP_1.3.
The solutions are: a) Work done by the force on the block: $\boxed{W}$ Joules b) Work done by gravity on the block: $\boxed{W_{\text{gravity}}}$ Joules c) Magnitude of the normal force: $\boxed{N}$ Newtons

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