Math  /  Data & Statistics

Question(0.37)(1.29m)=0.444 g/mLHCl36.465 mol30(0.37)\left(\frac{1.29}{m}\right)=0.444 \mathrm{~g} / \mathrm{mL} \mathrm{HCl} \quad \frac{36.465 \mathrm{~mol}}{30} A solution contains 50.0 grams of glycerol, C3H8O3\mathrm{C}_{3} \mathrm{H}_{8} \mathrm{O}_{3}, and 50.0 grams of water. The solution has a density of 1.10 g/mL1.10 \mathrm{~g} / \mathrm{mL}. Calculate the following: a) Weight %\% of C3H8O3\mathrm{C}_{3} \mathrm{H}_{8} \mathrm{O}_{3} in this solution. 501000=50%\frac{50}{1000}=50 \% b) Molality of C3H8O3\mathrm{C}_{3} \mathrm{H}_{8} \mathrm{O}_{3} in this solution. M=n sowt  soleat ky=0.54mI10.05=10.8M\mathrm{M}=\frac{n \text { sowt }}{\text { soleat } \mathrm{ky}}=\frac{0.54 \mathrm{mI1}}{0.05}=10.8 \mathrm{M} c) Mole Fraction of C3H8O3\mathrm{C}_{3} \mathrm{H}_{8} \mathrm{O}_{3} in this solution. x=0.542.πx=\frac{0.54}{2 . \pi} d) Molarity of C3H8O3\mathrm{C}_{3} \mathrm{H}_{8} \mathrm{O}_{3} in this solution. m=nc=0.54m=\frac{n}{c}=0.54

Studdy Solution
Weight percent: **50.0%** Molality: **10.9 m** Mole fraction: **0.164** Molarity: **5.97 M**

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