Math  /  Trigonometry

QuestionL steps for full marks as required. Correct answer with NO work shown = NO ma
1. Determine the exact values of the six trigonometric ratios for 585585^{\circ}. [8.1] [2 marks]

Studdy Solution
Calculate the remaining trigonometric ratios:
- tan(225)=sin(225)cos(225)=2222=1\tan(225^\circ) = \frac{\sin(225^\circ)}{\cos(225^\circ)} = \frac{-\frac{\sqrt{2}}{2}}{-\frac{\sqrt{2}}{2}} = 1 - csc(225)=1sin(225)=2\csc(225^\circ) = \frac{1}{\sin(225^\circ)} = -\sqrt{2} - sec(225)=1cos(225)=2\sec(225^\circ) = \frac{1}{\cos(225^\circ)} = -\sqrt{2} - cot(225)=1tan(225)=1\cot(225^\circ) = \frac{1}{\tan(225^\circ)} = 1
The exact values of the six trigonometric ratios for 585 585^\circ are:
sin(585)=22,cos(585)=22,tan(585)=1\sin(585^\circ) = -\frac{\sqrt{2}}{2}, \quad \cos(585^\circ) = -\frac{\sqrt{2}}{2}, \quad \tan(585^\circ) = 1
csc(585)=2,sec(585)=2,cot(585)=1\csc(585^\circ) = -\sqrt{2}, \quad \sec(585^\circ) = -\sqrt{2}, \quad \cot(585^\circ) = 1

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