Math  /  Calculus

Question(1 point) a. Set up an integral for finding the Laplace transform of the following function: f(t)={0,0t<6t3,6t.f(t)=\left\{\begin{array}{ll} 0, & 0 \leq t<6 \\ t-3, & 6 \leq t . \end{array}\right. F(s)=L{f(t)}=ABF(s)=\mathcal{L}\{f(t)\}=\int_{A}^{B} \square help (formulas) where A=A= \square and B=B= \square b. Find the antiderivative (with constant term 0 ) corresponding to the previous part. \square c. Evaluate appropriate limits to compute the Laplace transform of f(t)f(t) : F(s)=L{f(t)}=F(s)=\mathcal{L}\{f(t)\}= \square d. Where does the Laplace transform you found exist? In other words, what is the domain of F(s)F(s) ? \square help (inequalities)

Studdy Solution
F(s)=L{f(t)}=6(t3)estdt=(3s1)e6ss2F(s) = \mathcal{L}\{f(t)\} = \int_{6}^{\infty} (t - 3)e^{-st} \, dt = \frac{(3s - 1)e^{-6s}}{s^2} for s>0s > 0.

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