Math  /  Calculus

Question(1 point) According to a simple physiological model, an athletic adult male needs 20 calories per day per pound of body weight to maintain his weight. If he consumes more or fewer calories than those required to maintain his weight, his weight changes at a rate proportional to the difference between the number of calories consumed and the number needed to maintain his current weight; the constant of proportionality is 1/35001 / 3500 pounds per calorie. Suppose that a particular person has a constant caloric intake of HH calories per day. Let W(t)W(t) be the person's weight in pounds at time tt (measured in days). (a) What differential equation has solution W(t)W(t) ? dWdt=\frac{d W}{d t}= (Your answer may involve W,H\mathbf{W}, \boldsymbol{H} and values given in the problem.) (b) If the person starts out weighing 150 pounds and consumes 3100 calories a day. What happens to the person's weight as tt \rightarrow \infty ? WW \rightarrow
Note: You can earn partial credit on this problem.

Studdy Solution
(a) The differential equation is: dWdt=13500(H20W) \frac{dW}{dt} = \frac{1}{3500}(H - 20W) (b) As tt \rightarrow \infty, W155W \rightarrow 155 pounds.

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