Question(1 point)
Evaluate the limit using L'Hospital's rule if necessary. $$\lim _{x \rightarrow+\infty} \frac{x^{16}}{e^{x}}$$
Answer: $\square$

Studdy Solution
Continue applying L'Hospital's Rule 16 times in total:
After 16 applications, the numerator becomes a constant (the derivative of $x^0$) and the denominator remains $e^x$.
The final limit is:
$\lim_{x \rightarrow +\infty} \frac{16!}{e^x} = 0$
since $e^x$ grows much faster than any constant.
The value of the limit is:
$\boxed{0}$