Question(1 point) If you rewrite the expression $$2 \log _{5} x-4 \log _{5}\left(x^{2}+1\right)+5 \log _{5}(x-1)$$ as a single logarithm $\log _{5} A$, then: $$A=$$ help (formulas)

Studdy Solution
The expression is now a single logarithm:
$$\log_{5} A$$
Where:
$$A = \frac{x^2 \cdot (x - 1)^5}{(x^2 + 1)^4}$$
The value of $A$ is:
$$\boxed{\frac{x^2 \cdot (x - 1)^5}{(x^2 + 1)^4}}$$