Math  /  Arithmetic

Question Solve the following simple arithmetic expressions: 1) 120+12)+4=120+12)+4= 2) 50+6(114)=50+6 *(11-4)= 3) 50+6×114=50+6 \times 11-4= 4) 9(128)+28÷7=9 *(12-8)+28 \div 7= 5) 18(215)+(2218)=18-(21-5)+(22-18)= 6) 7×2(9+2)+14=7 \times 2-(9+2)+14= 7) (6÷3+5)×(114)=(6 \div 3+5) \times(11-4)= 8) 9×3+(2018)×48=9 \times 3+(20-18) \times 4-8= 9) (3717)×(240÷20)22×4=(37-17) \times(240 \div 20)-22 \times 4= 10) 11×4(6+3+13)÷2=3311 \times 4-(6+3+13) \div 2=33

Studdy Solution
Finally, subtract the result of the division from the result of the multiplication.
4411=3344 - 11 = 33
The solution to the tenth expression is 3333.

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