Math  /  Algebra

Question11. Find the value of xx. xlog27=7x^{\log _{2} 7}=7

Studdy Solution
Since log27 \log_{2} 7 is a common factor on both sides, divide both sides by log27 \log_{2} 7 to isolate log2x \log_{2} x :
log2x=1 \log_{2} x = 1
Convert the logarithmic equation to its exponential form to solve for x x :
x=21 x = 2^1
x=2 x = 2
The value of x x is:
2 \boxed{2}

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