Math  /  Trigonometry

Question11. Given the following graph of y=f(x)y=f(x) : a) Determine an equation of the graph in the form y=asin(b(xc))+dy=a \sin (b(x-c))+d. y=2sin(23(x3π2))+0y=2 \sin \left(\frac{2}{3}\left(x-\frac{3 \pi}{2}\right)\right)+0 b) Determine an equation of the graph in the form y=acos(b(xc))+dy=a \cos (b(x-c))+d.

Studdy Solution
The sine equation is y=2sin(23(x3π2)).y = 2\sin\left(\frac{2}{3}\left(x - \frac{3\pi}{2}\right)\right). The cosine equation is y=2cos(23(x+3π4)).y = 2\cos\left(\frac{2}{3}\left(x + \frac{3\pi}{4}\right)\right).

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