Question11. If $K_{\mathrm{M}}=2 \mathrm{mM}$, and $v_{o}=100 \mu \mathrm{~mol} /(\mathrm{mL} \cdot \mathrm{s})$ when [ S$]=2 \mathrm{mM}$, what is the velocity, $v_{\mathrm{o}}$, for the reaction when $[\mathrm{S}]=18 \mathrm{mM}$ ? 5

Studdy Solution
Calculate the new velocity, $v_{o}$, for $[\mathrm{S}]=18 \, \mathrm{mM}$.
Use the Michaelis-Menten equation: $$v_{o} = \frac{200 \cdot 18}{2 + 18}$$
Simplify: $$v_{o} = \frac{3600}{20}$$
Calculate: $$v_{o} = 180 \, \mu \mathrm{mol} /(\mathrm{mL} \cdot \mathrm{s})$$
The velocity, $v_{o}$, for the reaction when $[\mathrm{S}]=18 \, \mathrm{mM}$ is:
$\boxed{180 \, \mu \mathrm{mol} /(\mathrm{mL} \cdot \mathrm{s})}$