Math  /  Calculus

Question11. Let a function y=f(x)y=f(x) be given by the equation y3+y=2x2y^{3}+y=2 x^{2}, and also note that the points (1,1)(-1,1), (0,0)(0,0) and (1,1)(1,1) lie on its graph. Complete the following table: \begin{tabular}{l|ccc} xx & -1 & 0 & 1 \\ \hlinef(x)f^{\prime \prime}(x) & AA & BB & CC \end{tabular} (a) A=1,B=0,C=1A=-1, B=0, C=-1 (b) A=1,B=2,C=1A=-1, B=2, C=-1 (c) A=1,B=4,C=1A=-1, B=4, C=-1 (d) A=12,B=4,C=12A=-\frac{1}{2}, B=4, C=-\frac{1}{2} (e) A=0,B=1,C=0A=0, B=1, C=0

Studdy Solution
Seçenekleri kontrol edin:
(a) A=1,B=0,C=1 A=-1, B=0, C=-1 (Yanlış) (b) A=1,B=2,C=1 A=-1, B=2, C=-1 (Yanlış) (c) A=1,B=4,C=1 A=-1, B=4, C=-1 (Doğru) (d) A=12,B=4,C=12 A=-\frac{1}{2}, B=4, C=-\frac{1}{2} (Yanlış) (e) A=0,B=1,C=0 A=0, B=1, C=0 (Yanlış)
Doğru cevap (c) seçeneğidir.
Cevap: (c) A=1,B=4,C=1 A=-1, B=4, C=-1

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