Math  /  Geometry

Question11. What is the slope of the line that runs between the points (2,1)(-2,1) and (3,6)(3,6) ? Assign your variables and use the slope formula. x1=y1=x2=y2=m=y2y1x2x1==\begin{array}{l} x_{1}= \\ y_{1}= \\ x_{2}= \\ y_{2}= \\ m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}=\square= \end{array}

Studdy Solution
Simplify the expression to find the slope mm.
m=613(2)=53+2=55=1 m = \frac{6 - 1}{3 - (-2)} = \frac{5}{3 + 2} = \frac{5}{5} = 1
The slope of the line that runs between the points (2,1)(-2,1) and (3,6)(3,6) is 11.

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