Math  /  Algebra

Question12. Find the square root of (a) 5+12i5+12 i

Studdy Solution
Use the modulus and argument to find the square root of the complex number. The square root is given by:
r(cos(θ/2)+isin(θ/2)) \sqrt{r}(\cos(\theta/2) + i\sin(\theta/2))
Calculate r\sqrt{r}:
r=13 \sqrt{r} = \sqrt{13}
Calculate θ/2\theta/2:
θ/20.588 radians \theta/2 \approx 0.588 \text{ radians}
Calculate cos(θ/2)\cos(\theta/2) and sin(θ/2)\sin(\theta/2):
cos(0.588)0.832 \cos(0.588) \approx 0.832 sin(0.588)0.555 \sin(0.588) \approx 0.555
Thus, the square root of 5+12i5 + 12i is:
13(0.832+0.555i) \sqrt{13}(0.832 + 0.555i)
Calculate the final expression:
3.0+2.0i \approx 3.0 + 2.0i
The square root of 5+12i5 + 12i is approximately:
3.0+2.0i \boxed{3.0 + 2.0i}

View Full Solution - Free
Was this helpful?

Studdy solves anything!

banner

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

ParentsInfluencer programContactPolicyTerms
TwitterInstagramFacebookTikTokDiscord