Math / AlgebraQuestion14. 7b24ac⋅8ac221b3c=\frac{7b^2}{4ac} \cdot \frac{8ac^2}{21b^3c} =4ac7b2⋅21b3c8ac2=Studdy SolutionThe simplified expression is 23b\frac{2}{3b}3b2.View Full Solution - FreeWas this helpful?