Math  /  Algebra

Question14 z2+10z24=0z^{2}+10 z-24=0
What is one of the solutions to the given equation?

Studdy Solution
Calculate the two possible solutions for z z :
1. z=10+142=42=2 z = \frac{-10 + 14}{2} = \frac{4}{2} = 2
2. z=10142=242=12 z = \frac{-10 - 14}{2} = \frac{-24}{2} = -12

One of the solutions to the equation is:
2 \boxed{2}

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