Question15. What is the solution to $4(y-3)+19=8(2 y+3)+7$ ?

Studdy Solution
Check the solution by substituting $y = -2$ back into the original equation:
Original equation: $$4(y-3) + 19 = 8(2y+3) + 7$$
Substitute $y = -2$:
Left side: $$4(-2 - 3) + 19 = 4(-5) + 19 = -20 + 19 = -1$$
Right side: $$8(2(-2) + 3) + 7 = 8(-4 + 3) + 7 = 8(-1) + 7 = -8 + 7 = -1$$
Both sides are equal, confirming the solution is correct.
The solution is: $$\boxed{-2}$$