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Math  /  Math Statement

QuestionCalculate the units for: (163.mgdL)(10−3 g1mg)(1dL10−1 L)(10−3 L1 mL) \left(163 . \frac{\mathrm{mg}}{\mathrm{dL}}\right)\left(\frac{10^{-3} \mathrm{~g}}{1 \mathrm{mg}}\right)\left(\frac{1 \mathrm{dL}}{10^{-1} \mathrm{~L}}\right)\left(\frac{10^{-3} \mathrm{~L}}{1 \mathrm{~mL}}\right).

Studdy Solution
The numerical part of the expression remains the same as there are no numerical values to simplify.
163.gm=163.gm163 . \frac{\mathrm{g}}{\mathrm{m}} =163 . \frac{\mathrm{g}}{\mathrm{m}}So, the units of the student's answer are g/mL.

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