Math  /  Algebra

Question19. (a) These are the first four terms in a sequence. (i) Find an expression, in terms of nn, for the nth n^{\text {th }} term of the sequence. 23+(4×n)23+(4×n) Answer \begin{array}{l} 23+(4 \times n) \\ \begin{array}{ll} & 23+(4 \times n) \\ \text { Answer } \end{array} \end{array} (ii) Explain why it is not possible for a term in the sequence to be a multiple of 8 .
Answer \qquad \qquad [1] (iii) Write down the first four terms of a sequence in which some, but not all, of the terms are multiples of 8 .
Answer \qquad [2] (b) The nth n^{\text {th }} term of a difference sequence is given by Tn=5n+41924nT_{n}=\frac{5 n+4}{192-4 n}. (i) Use the formula to find T5T_{5}.
Give your answer as a fraction in its simplest form.
Answer \qquad [1] (ii) The value of TkT_{k} can be simplified to 49\frac{4}{9}. Find the value of kk.
Answer \qquad [3] (iii) Suggest a value of nn such that the value of TnT_{n} is greater than 1 .

Studdy Solution
(a)(i) 4n+194n + 19 (a)(ii) Explained above. (a)(iii) 4, 8, 12, 16 (b)(i) 29172\frac{29}{172} (b)(ii) k=12k = 12 (b)(iii) n=30n = 30 (or any larger suitable value)

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