Math  /  Math Statement

QuestionFind the x x -coordinate of the inflection point of f(x)=1x(3t6t2)dt f(x)=\int_{1}^{x}(3t-6t^{2})dt . Options: (a) 14-\frac{1}{4} (b) 14\frac{1}{4} (c) 0 (d) 12\frac{1}{2}. Evaluate sin(3x)dx \int \sin(3x)dx . Options: (a) 3cos(3x)+C3\cos(3x)+C (b) 13cos(3x)+C\frac{1}{3}\cos(3x)+C (c) 3cos(3x)+C-3\cos(3x)+C (d) 13cos(3x)+C-\frac{1}{3}\cos(3x)+C. Count removable discontinuities of y=x+2x4+16 y=\frac{x+2}{x^{4}+16} . Options: (a) one (b) two (c) three (d) four.

Studdy Solution
For Problem21, a removable discontinuity occurs when a factor in the denominator of a rational function cancels out with a factor in the numerator.
For y=x+2x4+16 y=\frac{x+2}{x^{4}+16} , x = -2 is a removable discontinuity.
But the denominator x4+16 x^{4} +16 has no real roots, so there's no other values of x that make the function undefined.
Therefore, y has one removable discontinuity at x = -2.

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