Math  /  Algebra

Question2 4. The admission fee at a small fair is $1.50\$ 1.50 for children and $4.00\$ 4.00 for adults. On a certain day, $5,050\$ 5,050 is collected. If 1,00 adults attended the fair, write and solve a linear equation to find the number of children that attended. x=1.50y=4.06x=1.50 \quad y=4.06 c=c= toal
Equation: 1.50x+4y=5,0501.50 x+4 y=5,050 Solution:

Studdy Solution
Solve the equation for the unknown variable x x .
First, calculate the total revenue from adults:
4.00×1,000=4,000 4.00 \times 1,000 = 4,000
Substitute this back into the equation:
1.50x+4,000=5,050 1.50x + 4,000 = 5,050
Subtract 4,000 from both sides to isolate the term with x x :
1.50x=5,0504,000 1.50x = 5,050 - 4,000 1.50x=1,050 1.50x = 1,050
Divide both sides by 1.50 to solve for x x :
x=1,0501.50 x = \frac{1,050}{1.50} x=700 x = 700
The number of children that attended the fair is:
700 \boxed{700}

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