Math  /  Calculus

Question2.) (5pts) Evaluate the limit, if it exists. limx2x+2x3+8\lim _{x \rightarrow-2} \frac{x+2}{x^{3}+8}

Studdy Solution
Evaluate the limit of the simplified expression as x2 x \to -2 :
limx21x22x+4 \lim_{x \to -2} \frac{1}{x^2-2x+4}
Substitute x=2 x = -2 :
=1(2)22(2)+4 = \frac{1}{(-2)^2 - 2(-2) + 4} =14+4+4 = \frac{1}{4 + 4 + 4} =112 = \frac{1}{12}
The value of the limit is:
112 \boxed{\frac{1}{12}}

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