Question(2 points) Solve the rational exponent equation. Use factoring where necessary, If there is more than one answer, enter a comma separated list. $$x^{2 / 3}=4$$ $$x=$$ $\square$ holp (numbers)

Studdy Solution
Verify both solutions by substituting back into the original equation:
For $x = 8$:
$$8^{2/3} = (8^{1/3})^2 = 2^2 = 4$$
For $x = -8$:
$$(-8)^{2/3} = ((-8)^{1/3})^2 = (-2)^2 = 4$$
Both solutions satisfy the original equation.
The solutions are:
$$x = 8, -8$$