Math  /  Trigonometry

Question2 Rewrite cos4x\cos 4 x in terms of cosx\cos x and powers of cosx\cos x. ( 3 points) (Note: The answer cannot have multiple angles of cosines)

Studdy Solution
Expand and simplify the expression:
First, expand (2cos2x1)2(2\cos^2 x - 1)^2:
(2cos2x1)2=4cos4x4cos2x+1(2\cos^2 x - 1)^2 = 4\cos^4 x - 4\cos^2 x + 1
Substitute back into the expression for cos4x\cos 4x:
cos4x=2(4cos4x4cos2x+1)1\cos 4x = 2(4\cos^4 x - 4\cos^2 x + 1) - 1
Simplify:
cos4x=8cos4x8cos2x+21\cos 4x = 8\cos^4 x - 8\cos^2 x + 2 - 1
cos4x=8cos4x8cos2x+1\cos 4x = 8\cos^4 x - 8\cos^2 x + 1
The expression for cos4x\cos 4x in terms of cosx\cos x is:
8cos4x8cos2x+1\boxed{8\cos^4 x - 8\cos^2 x + 1}

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