Math  /  Geometry

Question2. What is the magnitude of resultant vector where u=42,2 and v=52,3\vec{u}=\langle-4 \sqrt{2},-2\rangle \text { and } \vec{v}=\langle 5 \sqrt{2}, 3\rangle

Studdy Solution
Calculate the magnitude of the resultant vector r\vec{r}:
The formula for the magnitude of a vector a,b\langle a, b \rangle is:
r=a2+b2|\vec{r}| = \sqrt{a^2 + b^2}
Substitute the components of r\vec{r}:
r=(2)2+(1)2|\vec{r}| = \sqrt{(\sqrt{2})^2 + (1)^2}
r=2+1|\vec{r}| = \sqrt{2 + 1}
r=3|\vec{r}| = \sqrt{3}
The magnitude of the resultant vector is:
3 \boxed{\sqrt{3}}

View Full Solution - Free
Was this helpful?

Studdy solves anything!

banner

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

ParentsInfluencer programContactPolicyTerms
TwitterInstagramFacebookTikTokDiscord