Question20. А пэгийг дайрсан, өгсөн шулуунтаи параллел шулууны тэгшитгэлийг бич. a. $A(3,-1), y=5 x-4$
6. $A(0,0),-3 y+2 x+8=0$ B. $A(2,4), 0.3 y-4 x=9$ г. $A\left(1, \frac{1}{4}\right), y=3 x+2$ д. $A(1,0), \frac{1}{2} y-x+7=0$ е. $A(-3,4), 4 y-\frac{2}{3} x=1$
21. $B$ цэгийг дайрсан, өгсөн шулуунтай перпендикуляр шулууны тэгшитгэлийг бич. a. $B(2,-2), y=3 x-1$ б. $B(0,-3), 5 y+x+2=0$ B. $B(-2,4), 6 y+x=1$ г. $B(0.5,-4), \frac{1}{3} y-3 x=4$ д. $B\left(4, \frac{1}{2}\right),-y+5 x+0.5=0$ e. $B(-1,3),-\frac{1}{5} y-x=3$

Studdy Solution
Use the point-slope form to write the equation of the new line. For each part:
a. Point: $A(3, -1)$ - Equation: $y + 1 = 5(x - 3)$ - Simplified: $y = 5x - 16$
b. Point: $A(0, 0)$ - Equation: $y - 0 = \frac{2}{3}(x - 0)$ - Simplified: $y = \frac{2}{3}x$
c. Point: $A(2, 4)$ - Equation: $y - 4 = \frac{40}{3}(x - 2)$ - Simplified: $y = \frac{40}{3}x - \frac{68}{3}$
d. Point: $A\left(1, \frac{1}{4}\right)$ - Equation: $y - \frac{1}{4} = 3(x - 1)$ - Simplified: $y = 3x - \frac{11}{4}$
e. Point: $A(1, 0)$ - Equation: $y - 0 = 2(x - 1)$ - Simplified: $y = 2x - 2$
f. Point: $A(-3, 4)$ - Equation: $y - 4 = \frac{1}{6}(x + 3)$ - Simplified: $y = \frac{1}{6}x + \frac{23}{6}$