QuestionAn object is launched with an initial velocity of 48 ft/s from 80 ft. Find average velocity from $t=0$ to $t=2$ and $t=2$ to $t=4$. Use $h(t)=-16 t^{2}+48 t+80$.

Studdy Solution
Calculate the average velocity from $t=$ to $t=4$ seconds.
$$Average\, velocity = \frac{-112}{} = -56\, feet/second$$The average velocity in the first two seconds after the object is launched is16 feet per second, and the average velocity from $t=$ to $t=4$ seconds is -56 feet per second.