Math  /  Data & Statistics

Question23. Car repairs A consumer organization estimates that over a oneyear period 17%17 \% of cars will need to be repaired once, 7%7 \% will need repairs twice, and 4%4 \% will require three or more repairs. What is the probability that a car chosen at random will need a) no repairs? b) no more than one repair? c) some repairs?

Studdy Solution
Calculate the probability of some repairs.
The probability of some repairs is the complement of the probability of no repairs. Therefore:
100%72%=28% 100\% - 72\% = 28\%
The probabilities are: a) Probability of no repairs: 72%\boxed{72\%} b) Probability of no more than one repair: 89%\boxed{89\%} c) Probability of some repairs: 28%\boxed{28\%}

View Full Solution - Free
Was this helpful?

Studdy solves anything!

banner

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

ParentsInfluencer programContactPolicyTerms
TwitterInstagramFacebookTikTokDiscord