Question23. In the figure, the line $k x+4 y-12=0$ cuts the $\mathrm{x}-\mathrm{axis}$ at A and the $\mathrm{y}-\mathrm{axis}$ at B . If the area of $\triangle \mathrm{OAB}$ is 6 square units, then $k=$ Av) 1 B. 3 C. 5 D. 7

Studdy Solution
Set up an equation for the area and solve for $k$ .
Given that the area is 6 square units:
$\frac{18}{k} = 6$
Multiply both sides by $k$ :
$18 = 6k$
Divide both sides by 6:
$k = 3$
The value of $k$ is:
$\boxed{3}$

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