Math  /  Algebra

QuestionSolve the equations and verify your answers:
1. 5r26=19\frac{5 r}{2}-6=19
2. n38=2\frac{n}{3}-8=-2
3. 5+x4=15+\frac{x}{4}=1
4. h34=13-\frac{h}{3}-4=13
5. 5(1+n)=55(1+n)=-5

Studdy Solution
Assumptions1. The equations are linear equations. . The solutions to the equations are real numbers.
Problem29First, we need to isolate the term with the variable on one side of the equation. We can do this by adding6 to both sides of the equation.
5r6+6=19+6\frac{5 r}{} -6 +6 =19 +63implify the equation.
5r=25\frac{5 r}{} =254To solve for r, multiply both sides of the equation by/5.
r=255×5r = \frac{25}{5} \times \frac{}{5}5Calculate the value of r.
r=10r =10Problem306First, we need to isolate the term with the variable on one side of the equation. We can do this by adding8 to both sides of the equation.
n38+8=+8\frac{n}{3} -8 +8 = - +87implify the equation.
n3=6\frac{n}{3} =68To solve for n, multiply both sides of the equation by3.
n=6×3n =6 \times39Calculate the value of n.
n=18n =18Problem3110First, we need to isolate the term with the variable on one side of the equation. We can do this by subtracting5 from both sides of the equation.
5+x45=155 + \frac{x}{4} -5 =1 -511implify the equation.
x4=4\frac{x}{4} = -412To solve for x, multiply both sides of the equation by4.
x=4×4x = -4 \times413Calculate the value of x.
x=16x = -16Problem3214First, we need to isolate the term with the variable on one side of the equation. We can do this by adding4 to both sides of the equation.
h34+4=13+4-\frac{h}{3} -4 +4 =13 +415implify the equation.
h3=17-\frac{h}{3} =1716To solve for h, multiply both sides of the equation by -3.
h=17×3h =17 \times -317Calculate the value of h.
h=51h = -51Problem3318First, we need to distribute the5 into the parentheses.
5×1+5×n=55 \times1 +5 \times n = -519implify the equation.
5+5n=55 +5n = -520To isolate the term with the variable, subtract5 from both sides of the equation.
5+5n5=555 +5n -5 = -5 -521implify the equation.
5n=105n = -1022To solve for n, divide both sides of the equation by5.
n=105n = \frac{-10}{5}23Calculate the value of n.
n=n = -The solutions to the equations are r=10, n=18, x=-16, h=-51, n=-.

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