Math / CalculusQuestion29. ∫(x2−x+1)dxx2+x\int \frac{\left(x^{2}-x+1\right) d x}{x^{2}+x}∫x2+x(x2−x+1)dxStuddy SolutionCombine the results:∫x2−x+1x2+x dx=x+ln∣x∣−3ln∣x+1∣+C\int \frac{x^2 - x + 1}{x^2 + x} \, dx = x + \ln |x| - 3 \ln |x + 1| + C∫x2+xx2−x+1dx=x+ln∣x∣−3ln∣x+1∣+Cwhere CCC is the constant of integration. The antiderivative is:x+ln∣x∣−3ln∣x+1∣+C\boxed{x + \ln |x| - 3 \ln |x + 1| + C}x+ln∣x∣−3ln∣x+1∣+CView Full Solution - FreeWas this helpful?