Question$\frac{2^{n+1}-2^{n+2}}{2^{n-1}-2^{n-2}}$

Studdy Solution
Simplify the entire fraction by dividing the factored numerator by the factored denominator.
$$\frac{-2^{n+1}}{2^{n-2}}$$
Apply the properties of exponents:
$$= -2^{(n+1) - (n-2)}$$
$$= -2^{n+1-n+2}$$
$$= -2^{3}$$
$$= -8$$
The simplified expression is:
$$\boxed{-8}$$