Math  /  Algebra

Question[3] 3. Given f(x)=3k2xf(x)=3 k-2 x, find the value of kk if f1(5)=2f^{-1}(5)=-2.

Studdy Solution
Solve the equation 3k52=2\frac{3k - 5}{2} = -2 for kk.
2=3k52 -2 = \frac{3k - 5}{2} 4=3k5 -4 = 3k - 5 3k=1 3k = 1 k=13 k = \frac{1}{3}
The value of kk is 13\frac{1}{3}.

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