Math  /  Algebra

Question3. Given f(x)=3(x4)2+6f(x)=-3(x-4)^{2}+6, determine the following KEY features. a=2, h=4,k=6\mathrm{a}=\underline{-2}, \mathrm{~h}=4, \mathrm{k}=6 \begin{tabular}{|llllll|} \hline OPTIONS & -3 & 3 & -4 & 4 & 6 \\ \hline \end{tabular}
Vertex: \qquad \begin{tabular}{|lllll|} \hline OPTIONS & (4,6)(4,6) & (4,6)(-4,-6) & (4,6)(4,6) & (4,6)(-4,6) \\ \hline \end{tabular}
Axis of Symmetry: \qquad \begin{tabular}{|llll|} \hline OPTIONS x=4)(x2\quad x=4)(x-2 & x=4x=4 \\ \hline \end{tabular} Vertical Stretch (Narrow)/ Vertical Compression (Wide) / Neither: \qquad \begin{tabular}{|llll|} \hline OPTIONS & Stretch & Compression & Neither \\ \hline \end{tabular}
Horizontal Shift: \qquad
Vertical Shift: \qquad \begin{tabular}{|lllll|} \hline OPTIONS & Left 4 & Right 4 & Left 6 & Right 6 \\ \hline OPTIONS & Up 4 & Down 4 & Up 6 & Down 6 \\ \hline \end{tabular}
Direction of Opening: \qquad OPTIONS Up Down
Maximum or Minimum: \qquad OPTIONS Minimum Maximum
4. Given f(x)=x2+2x4f(x)=x^{2}+2 x-4, determine the following KEY features.

Vertex: \qquad
Domain: \qquad Interval of Increase: \qquad
Range: \qquad Interval of Decrease: \qquad

Studdy Solution
Since the parabola opens downward, the vertex represents a maximum point.
The key features are: - Vertex: (4,6)(4, 6) - Axis of Symmetry: x=4x = 4 - Vertical Stretch - Horizontal Shift: Right 4 - Vertical Shift: Up 6 - Direction of Opening: Down - Maximum
For the second function f(x)=x2+2x4 f(x) = x^2 + 2x - 4 , we will determine the following:

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