Math  /  Algebra

Question3KOH+H3PO4 K3PO4+3H2O3 \mathrm{KOH}+\mathrm{H}_{3} \mathrm{PO}_{4} \rightarrow \mathrm{~K}_{3} \mathrm{PO}_{4}+3 \mathrm{H}_{2} \mathrm{O} how many grams of potassium phosphate, K3PO4\mathrm{K}_{3} \mathrm{PO}_{4}, are produced from 30.3 g of potassium hydroxide, KOH ? mass of potassium phosphate: \square

Studdy Solution
Calculate the mass of K3PO4\mathrm{K}_{3} \mathrm{PO}_{4}.
Using the formula: Mass of K3PO4=Moles of K3PO4×Molar mass of K3PO4\text{Mass of } \mathrm{K}_{3} \mathrm{PO}_{4} = \text{Moles of } \mathrm{K}_{3} \mathrm{PO}_{4} \times \text{Molar mass of } \mathrm{K}_{3} \mathrm{PO}_{4}
Mass of K3PO4=0.180 moles×212.27 g/mol38.21 g\text{Mass of } \mathrm{K}_{3} \mathrm{PO}_{4} = 0.180 \text{ moles} \times 212.27 \text{ g/mol} \approx 38.21 \text{ g}
The mass of potassium phosphate produced is:
38.21 g\boxed{38.21 \text{ g}}

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