Question3) $\lim _{x \rightarrow 0} \frac{x^{2}}{e^{x}-1-x}$

Studdy Solution
Now substitute $x = 0$ into the simplified expression:
$$\lim_{x \rightarrow 0} \frac{2}{e^x} = \frac{2}{e^0} = \frac{2}{1} = 2$$
The value of the limit is:
$$\boxed{2}$$