Question3. Provet $\frac{\sin 4 \pm-\sin 2 \pi}{\sin 2 x}=\frac{\cos 3 x}{\cos x}$

Studdy Solution
The right-hand side of the original equation is:
$\frac{\cos 3x}{\cos x}$
Since the simplified left-hand side matches the right-hand side, the identity is proven.
The identity is proven to be true:
$\frac{\sin 4x - \sin 2x}{\sin 2x} = \frac{\cos 3x}{\cos x}$