Math  /  Calculus

Question3x2x3+8dx\int \frac{3 x^{2}}{x^{3}+8} d x

Studdy Solution
Substitute back u=x3+8u = x^3 + 8 to return to the original variable.
lnu+C=lnx3+8+C \ln |u| + C = \ln |x^3 + 8| + C
Solution: 3x2x3+8dx=lnx3+8+C \int \frac{3 x^{2}}{x^{3}+8} \, dx = \ln |x^3 + 8| + C

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