Question33) A power ice auger cost a retailer $\$ 327.00$ less $13 \%, 17 \%, 2.25 \%$. It carries a regular selling price on its price tag at a markup of $94 \%$ of the regular selling price. During the end-of-season sale, the power ice auger is marked down $30 \%$. What is the end-of-season sale price? 34) A piece of jewellery costing $\$ 150$ was marked up by $40 \%$ of the selling price. During the stores silver jubilee sale, the selling price was reduced to $\$ 175$. What was rate of markdown during the sale?

Studdy Solution
Calculate the end-of-season sale price after a $30\%$ markdown.
$$\text{End-of-season sale price} = 447.62 \times (1 - 0.30)$$ $$= 447.62 \times 0.70 = 313.33$$
The end-of-season sale price of the power ice auger is:
$\boxed{\$313.33}$
**Problem 34:**
STEP_1: Determine the selling price before the sale with a markup of $40\%$ of the selling price.
Let $S$ be the selling price before the sale.
The cost is $\$150$, and the markup is $40\%$ of the selling price:
$$S = 150 + 0.40S$$
Solve for $S$:
$$S - 0.40S = 150$$ $$0.60S = 150$$ $$S = \frac{150}{0.60} = 250$$
STEP_2: Calculate the rate of markdown during the sale.
The selling price during the sale is $\$175$.
$$\text{Markdown amount} = 250 - 175 = 75$$
$$\text{Rate of markdown} = \frac{75}{250} \times 100\% = 30\%$$
The rate of markdown during the sale is:
$\boxed{30\%}$