Question33. Fill in the blank. The sum of three consecutive counting numbers always has a divisor (other than 1 ) of $\qquad$ . Prove.

Studdy Solution
Factor the expression:
$$3n + 3 = 3(n + 1)$$
Since the expression is factored as $3(n + 1)$, it is clear that the sum $3n + 3$ is always divisible by 3.
The sum of three consecutive counting numbers always has a divisor (other than 1) of:
$\boxed{3}$