Math  /  Trigonometry

Question34sin(x+5.793)=34(cos)34 \sin (x+5.793) = 34 \left( \cos \square \right)
Hello there! It seems we have a math problem involving the verification of a trigonometric identity using the sum formula for sine. However, it looks like there is some missing information. Could you provide the result from part (a) or any specific details you have for this problem? This will help me guide you through the solution effectively.
34 \sin(x + 0.493)

Studdy Solution
Solve for \square in both scenarios:
1. x+5.793=π2 x + 5.793 = \frac{\pi}{2} - \square
=π2(x+5.793) \square = \frac{\pi}{2} - (x + 5.793)
2. x+5.793=π(π2) x + 5.793 = \pi - \left(\frac{\pi}{2} - \square\right)
x+5.793=π2+ x + 5.793 = \frac{\pi}{2} + \square
=x+5.793π2 \square = x + 5.793 - \frac{\pi}{2}
The expression \square can be either π2(x+5.793)\frac{\pi}{2} - (x + 5.793) or x+5.793π2x + 5.793 - \frac{\pi}{2}.

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