Math  /  Algebra

Question 4) 2x+11=12xx=b±b24ac2aa=b=c=\begin{array}{l} \text { 4) } \frac{2 x+1}{1}=\frac{-1}{2 x} \\ x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a} \\ a= \\ b= \\ c= \end{array}  5) 3x2+10x+9=68xx=b±b24ac2aa=b=c=\begin{array}{l} \text { 5) } 3 x^{2}+10 x+9=6-8 x \\ x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a} \\ a= \\ b= \\ c= \end{array}  6) 9=x(x+3)x=b±b24ac2aa=b=c=\begin{array}{l} \text { 6) } 9=x(x+3) \\ x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a} \\ a= \\ b= \\ c= \end{array}

Studdy Solution
Identify coefficients a a , b b , and c c :
a=1,b=3,c=9 a = 1, \quad b = 3, \quad c = -9
Now that we have identified the coefficients for each problem, we can apply the quadratic formula to find the solutions for x x .

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