Math  /  Trigonometry

Question4. AA and BB are walking on straight streets that meet at right angles. AA approaches the intersection at 2 m/sec2 \mathrm{~m} / \mathrm{sec} and BB moves away from the intersection at 1 m/sec1 \mathrm{~m} / \mathrm{sec}, as shown in the figure. At what rate is the angle θ\theta changing when AA is 10 m from the intersection and BB is 20 m from the intersection?

Studdy Solution
Solve for dθdt\frac{d\theta}{dt}:
dθdt=110\frac{d\theta}{dt} = \frac{1}{10}
The rate at which the angle θ\theta is changing is:
110rad/s\boxed{\frac{1}{10} \, \text{rad/s}}

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