Math  /  Geometry

Question4. Al punto B en este plano cartesiano, se le aplica una homotecia de centro AA y factor 2. ¿Cuáles son las coordenadas del punto que se obtiene?
A (4;3)(4 ; 3) (B) (10;6)(10 ; 6) (C) (12;8)(12 ; 8) (D) (14;8)(14 ; 8)

Studdy Solution
Calcular las nuevas coordenadas:
B(x,y)=(2+2×3,2+2×2) B'(x', y') = (2 + 2 \times 3, 2 + 2 \times 2) =(2+6,2+4) = (2 + 6, 2 + 4) =(8,6) = (8, 6)
Las coordenadas del punto transformado son:
(8,6) \boxed{(8, 6)}

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