Question$$4 \mathrm{HCl}(\mathrm{~g})+\mathrm{O}_{2}(\mathrm{~g}) \rightarrow 2 \mathrm{Cl}_{2}(\mathrm{~g})+2 \mathrm{H}_{2} \mathrm{O}(\mathrm{~g})$$
Calculate the number of grams of $\mathrm{Cl}_{2}$ formed when 0.225 mol HCl reacts with an excess of $\mathrm{O}_{2}$. mass: $\square$ $$\mathrm{g}$$

Studdy Solution
Convert moles of $\mathrm{Cl}_{2}$ to grams.
The molar mass of $\mathrm{Cl}_{2}$ is approximately $70.90 \, \text{g/mol}$.
Calculate the mass:
$\text{Mass of } \mathrm{Cl}_{2} = 0.1125 \, \text{mol Cl}_{2} \times 70.90 \, \text{g/mol}$
$\text{Mass of } \mathrm{Cl}_{2} = 7.978125 \, \text{g}$
Rounding to three significant figures, the mass of $\mathrm{Cl}_{2}$ is:
$\boxed{7.98 \, \text{g}}$