Math  /  Trigonometry

Question4sin(0.5x1)4 \sin (0.5 x-1) amplitude: period: c horizontal shift: \square

Studdy Solution
Determine the horizontal shift of the function y=4sin(0.5x1) y = 4 \sin(0.5x - 1) .
The horizontal shift is given by:
Horizontal Shift=CB \text{Horizontal Shift} = \frac{C}{B}
where C C is the constant subtracted from Bx Bx . Here, C=1 C = 1 and B=0.5 B = 0.5 .
Horizontal Shift=10.5=2 \text{Horizontal Shift} = \frac{1}{0.5} = 2
The amplitude is 4 \boxed{4} , the period is 4π \boxed{4\pi} , and the horizontal shift is 2 \boxed{2} .

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