Math  /  Calculus

Question44. The discriminant fxxfyyfxy2f_{x x} f_{y y}-f_{x y}{ }^{2} is zero at the origin for each of the following functions, so the Second Derivative Test fails there. Determine whether the function has a maximum, a minimum, or neither at the origin by imagining what the surface z=f(x,y)z=f(x, y) looks like. Describe your reasoning in each case. a. f(x,y)=x2y2f(x, y)=x^{2} y^{2} b. f(x,y)=1x2y2f(x, y)=1-x^{2} y^{2} c. f(x,y)=xy2f(x, y)=x y^{2} d. f(x,y)=x3y2f(x, y)=x^{3} y^{2} e. f(x,y)=x3y3f(x, y)=x^{3} y^{3} f. f(x,y)=x4y4f(x, y)=x^{4} y^{4}

Studdy Solution
Consider f(x,y)=x4y4 f(x, y) = x^4 y^4 .
- At the origin, f(0,0)=0 f(0, 0) = 0 . - Away from the origin, f(x,y)0 f(x, y) \geq 0 for all x,y x, y . - The surface z=x4y4 z = x^4 y^4 is always non-negative and flattens out at the origin.
Conclusion: The origin is a minimum point because the function is non-negative and zero at the origin.
The nature of the critical points at the origin for each function is as follows: a. Minimum b. Maximum c. Neither (saddle point) d. Neither (saddle point) e. Neither (saddle point) f. Minimum

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