Math  /  Calculus

Question5. Consider the oriented curve CC consisting of the following three line segments: from (0,0,0)(0,0,0) to (2,1,1)(2,1,1), followed by (2,1,1)(2,1,1) to (2,1,1)(2,-1,1), followed by (2,1,1)(2,-1,1) to (0,0,0)(0,0,0). (a) Let F(x,y,z)=xyı+yȷ+yzk\vec{F}(x, y, z)=x y \vec{\imath}+y \vec{\jmath}+y z \vec{k}. Compute the integral of F\vec{F} along CC. (b) Let F(x,y,z)=(z2cosy)ı(xz2siny)J+(2xzcosy)k\vec{F}(x, y, z)=\left(z^{2} \cos y\right) \vec{\imath}-\left(x z^{2} \sin y\right) \vec{J}+(2 x z \cos y) \vec{k}. Compute the integral of F\vec{F} along C.

Studdy Solution
Sum the integrals from each segment for part (b):
CFdr=I1+I2+I3\int_C \vec{F} \cdot d\vec{r} = I_1' + I_2' + I_3'
Where I1 I_1' , I2 I_2' , and I3 I_3' are the evaluated integrals for each segment.
The solution involves evaluating these integrals, which may require additional algebraic simplification and integration techniques.

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