Math  /  Algebra

Question5. Find the solutions to the following equation (x+3)2=36(x+3)^{2}=-36

Studdy Solution
Solve for xx by isolating it on one side of the equation. Subtract 3 from both sides:
x=3±6ix = -3 \pm 6i
This gives us the two complex solutions:
x=3+6iandx=36ix = -3 + 6i \quad \text{and} \quad x = -3 - 6i
The solutions to the equation (x+3)2=36(x+3)^2 = -36 are:
x=3+6iandx=36i x = -3 + 6i \quad \text{and} \quad x = -3 - 6i

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