Math  /  Calculus

Question5) y=(2x5+3)cosx2y=\left(2 x^{5}+3\right) \cos x^{2} (2x5+3)\left(2 x^{5}+3\right)

Studdy Solution
Simplify the resulting expression:
y=10x4cosx2(2x5+3)(2xsinx2) y' = 10x^4 \cos x^2 - (2x^5 + 3)(2x \sin x^2)
Distribute the terms:
y=10x4cosx24x6sinx26xsinx2 y' = 10x^4 \cos x^2 - 4x^6 \sin x^2 - 6x \sin x^2
The derivative of the function is:
y=10x4cosx24x6sinx26xsinx2 y' = 10x^4 \cos x^2 - 4x^6 \sin x^2 - 6x \sin x^2

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